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Abstract Algebra Homework HelpQ1: Prove that the set of integers under addition is a group.
See AnswerThe set of integers Z under addition forms a group because it satisfies closure, associativity, has an identity element (0), and each element has an inverse (-n for any n).
Q2: Show that the group of non-zero rational numbers under multiplication is abelian.
See AnswerThe group of non-zero rational numbers under multiplication is abelian because for any two elements a, b ∈ Q*, ab = ba, thus satisfying commutativity.
Q3: Define a ring and give an example of a commutative ring with unity.
See AnswerA ring is a set equipped with two binary operations: addition and multiplication, satisfying ring axioms. An example of a commutative ring with unity is the set of integers Z.
Q4: Prove that the identity element in a group is unique.
See AnswerAssume there are two identity elements, e and e'. By definition of identity, e * e' = e and e * e' = e'. Hence, e = e', proving the identity is unique.
Q5: Let G be a group and a ∈ G. Show that the inverse of a is unique.
See AnswerSuppose a has two inverses, b and c. Then, b = b * e = b * (a * c) = (b * a) * c = e * c = c. Therefore, the inverse of a is unique.
Q6: Prove that the set of even integers under addition forms a subgroup of the group of integers under addition.
See AnswerThe set of even integers is closed under addition, contains the identity element 0, and for every even integer, its inverse (negative) is also an even integer. Therefore, it forms a subgroup.
Q7: Is the set of 2x2 matrices with determinant 1 a group under matrix multiplication?
See AnswerYes, the set of 2x2 matrices with determinant 1, called SL(2, R), forms a group under matrix multiplication because it satisfies closure, associativity, has an identity element, and each element has an inverse.
Q8: Let R be a ring. Prove that R^n (n-tuples of elements of R) forms a module over R.
See AnswerR^n forms a module over R because it satisfies the axioms of a module: closure under addition, scalar multiplication, and distributive properties hold for R^n.
Q9: Prove that a finite group of prime order is cyclic.
See AnswerA group of prime order p has no proper subgroups and every element generates the entire group. Hence, the group is cyclic.
Q10: Show that the set of complex numbers under addition is a group.
See AnswerThe set of complex numbers under addition forms a group because it satisfies closure, associativity, has an identity element (0), and every element has an inverse (-z for any z).
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